Physics

# The dimensions of magnetic field in $M, L, T$ and $C$ (coulomb) are given as

$[MT^{-1}C^{-1}]$

##### SOLUTION
Force $F$ acting on charge $q$ moving with velocity $v$ in magnetic field $B$ is given as $F=qvB$ thus $B=\dfrac {F}{qv}$
$\therefore [B]=\dfrac {[F]}{[qv]}=\dfrac {MLT^{-2}}{C\times LT^{-1}}=[MT^{-1}C^{-1}]$

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Single Correct Medium Published on 18th 08, 2020
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