Physics

The dimensions of Planck's constant is the same as the product of

force, displacement and time

SOLUTION
$E=h\nu$
$\implies$ Planck's constant $h=\dfrac{E}{\nu}$
Dimension of energy=$[ML^2T^{-2}]$
Dimension of $\nu=[T^{-1}]$
Thus dimension of $h=[ML^2T^{-1}]$
Dimension of Force $=[MLT^{-2}]$
Dimension of Displacement=$[L]$
Dimension of Time$=[T]$
Thus dimension of $Force\times displacement\times time=[ML^2T^{-1}]$=Dimension of Planck's constant

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Single Correct Medium Published on 18th 08, 2020
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