Physics

The dimensions of Planck's constant is the same as the product of


ANSWER

force, displacement and time


SOLUTION
$$E=h\nu$$
$$\implies $$ Planck's constant $$h=\dfrac{E}{\nu}$$
Dimension of energy=$$[ML^2T^{-2}]$$
Dimension of $$\nu=[T^{-1}]$$
Thus dimension of $$h=[ML^2T^{-1}]$$
Dimension of Force $$=[MLT^{-2}]$$
Dimension of Displacement=$$[L]$$
Dimension of Time$$=[T]$$
Thus dimension of $$Force\times displacement\times time=[ML^2T^{-1}]$$=Dimension of Planck's constant
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