Physics

# The displacement in ${ n }^{ th }$ second of uniformly acelerated motion is given by ${ S }_{ { n }^{ th } }=u+\dfrac { a }{ 2 } \left( 2n-1 \right)$. This equation is dimensionally

correct

##### SOLUTION

Since:

$\underset{L}{S_{n^{th}}}=\underset{L}{[u(n)+ \frac{1}{2}an^{2}]}- \underset{L}{[u(n-1)+ \frac{1}{2}a(n-1)^{2}]}$

Hence dimensionally correct, as n has been cancelled out during calculation .

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Single Correct Medium Published on 18th 08, 2020
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