Physics

The displacement in $${ n }^{ th }$$ second of uniformly acelerated motion is given by $${ S }_{ { n }^{ th } }=u+\dfrac { a }{ 2 } \left( 2n-1 \right) $$. This equation is dimensionally


ANSWER

correct


SOLUTION

Since:

$$\underset{L}{S_{n^{th}}}=\underset{L}{[u(n)+ \frac{1}{2}an^{2}]}- \underset{L}{[u(n-1)+ \frac{1}{2}a(n-1)^{2}]}$$

Hence dimensionally correct, as n has been cancelled out during calculation .

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