Physics

# The distance traveled by a body in time $'t'$ is given by $x=a+bt+{ ct }^{ 2 }$ where $x$ is distance, $t$ is time $a, b$ and $c$ are constants. The dimensional formula for $a, b$ and $c$ respectively are :

$L^1, { L }^{ 1 }{ T }^{ -1 },{ L }^{ 1 }{ T }^{ -2 }$

##### SOLUTION

$x ={a+bt+ct^{2}}$

$L^1=a$
$L^1=bt$
$\Rightarrow b=L^1T^{-1}$
$cT^{2}= L\Rightarrow c=L^1T^{-2}$

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Single Correct Medium Published on 18th 08, 2020
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