Physics

The fundamental unit which has the same power in the dimension formula of surface tension and viscosity is


ANSWER

mass


SOLUTION

$$F=\mu A\dfrac { u }{ y } \\ \Longrightarrow \mu =\dfrac { Fy }{ uA } $$

$$F =$$ Force        
Dimensions are $$[MLT^{-2}]$$
$$u=$$ Speed 
Dimensions are $$[LT^{-1}]$$
$$y=$$ Distance 
Dimensions are $$[L]$$
$$\mu =$$ coefficient of viscosity
$$A =$$ area of the cross section. 
Dimensions are $$[L^2]$$

Dimensions for coefficient of viscosity will be $$\dfrac { [{ MLT }^{ -2 }]*[L] }{ { [LT }^{ -1 }]*[{ L }^{ 2 }] } =[M{ L }^{ -1 }{ T }^{ -1 }]$$

Tension is a force used in a different context.
Dimensions are $$[MLT^{-2}]$$

Only mass has same power in both viscosity and tension.
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