Physics

The fundamental unit which has the same power in the dimensional formula of surface tension and coefficient of viscosity is:


ANSWER

mass


SOLUTION
Surface tension $$= \dfrac{F}{l} = \dfrac{M^{1}L^{1}T^{-2}}{L^{1}} = M^{1}T^{-2}$$
Coeff of viscosity $$= \dfrac{k}{qA\dfrac{dv}{dz}} = \dfrac{M^{1}L^{1}T^{-2}}{\dfrac{L^{2}LT^{-1}}{L}} = M^{1}L^{-1}T^{-1}$$
Hence, mass has the same power.
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