Physics

The least count of a stop watch is 0.2 second.The time of 20 oscillations of a pendulum is measured to be 25 seconds.The percentage error in time period is


ANSWER

0.8%


SOLUTION
Percentage error=$$\dfrac{least \quad count}{measurement} \times 100$$
$$=\dfrac{0.2}{25} \times 100=0.8$$ %
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Single Correct Medium Published on 18th 08, 2020
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