Physics

# The least count of a stop watch is $\dfrac{1}{5}$ second. The time of $20$ oscillations of a pendulum is measured to be $25$ seconds. The maximum percentage error in the measurement of time will be

$40$%

##### SOLUTION
$20$ Oscillations $=25$ sec
$1$ Oscillations $=\dfrac{25}{20}$ sec
T= Times period = $\left(\dfrac{25}{20}\right)$ sec
Least Count =error =$\dfrac{1}{5}$ sec $=0.5$
% error $=\dfrac{error}{T}\times 100$
$=\dfrac{0.5}{25}\times 20$
$=40$%

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Single Correct Medium Published on 18th 08, 2020
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