Physics

The least count of a stop watch is $$\dfrac{1}{5}$$ second. The time of $$20$$ oscillations of a pendulum is measured to be $$25$$ seconds. The maximum percentage error in the measurement of time will be


ANSWER

$$40$$%


SOLUTION
$$20$$ Oscillations $$=25$$ sec
$$1$$ Oscillations $$=\dfrac{25}{20}$$ sec
T= Times period = $$\left(\dfrac{25}{20}\right)$$ sec
Least Count =error =$$\dfrac{1}{5}$$ sec $$=0.5$$
% error $$=\dfrac{error}{T}\times 100$$
$$=\dfrac{0.5}{25}\times 20$$
$$=40$$%
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