Physics

The period of osciflation of a simple pendulum in the recorded as $$2.63 \,sec, 2.42 \,sec, 2.42 \,sec, 2.71 \,sec$$ and $$2.80 \,sec$$ respectively. The average absolute error is


ANSWER

$$0.14 \,sec$$


SOLUTION
Average value $$=\dfrac{2.63+2.42+2.42+2.71+2.80}{5}$$
$$=2.6$$ sec
Now for
Average absolute error
$$|\Delta T_1|=|2.63-2.42|=0.21$$
$$|\Delta T_2|=2.42-2.42|=0.00$$
$$|\Delta T_3|=|2.42-2.71|=0.29$$
$$|\Delta T_4|=|2.71-2.80|=0.09$$
Mean absolute error
$$\Delta T=\dfrac{|\Delta T_1|+|\Delta T_2|+|\Delta T_3|+|\Delta T_4|}{4}$$
$$=\dfrac{0.59}{4}$$
$$=0.1475$$ sec.
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