Physics

# The period of osciflation of a simple pendulum in the recorded as $2.63 \,sec, 2.42 \,sec, 2.42 \,sec, 2.71 \,sec$ and $2.80 \,sec$ respectively. The average absolute error is

$0.14 \,sec$

##### SOLUTION
Average value $=\dfrac{2.63+2.42+2.42+2.71+2.80}{5}$
$=2.6$ sec
Now for
Average absolute error
$|\Delta T_1|=|2.63-2.42|=0.21$
$|\Delta T_2|=2.42-2.42|=0.00$
$|\Delta T_3|=|2.42-2.71|=0.29$
$|\Delta T_4|=|2.71-2.80|=0.09$
Mean absolute error
$\Delta T=\dfrac{|\Delta T_1|+|\Delta T_2|+|\Delta T_3|+|\Delta T_4|}{4}$
$=\dfrac{0.59}{4}$
$=0.1475$ sec.

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Single Correct Medium Published on 18th 08, 2020
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