Physics

The physical quantities not having same dimensions are :


ANSWER

momentum and Plancks constant


SOLUTION
$$\dfrac{1}{\sqrt{\mu _{0}\epsilon _{0}}}=\sqrt{L^{2}T^{-2}}=LT^{-1}$$
Speed $$=LT^{-1}$$
Stress, Young's modulus 
$$=\dfrac{MLT^{-2}}{L^{2}}=ML^{-1}T^{-2}$$
Momentum $$=MLT^{-1}$$
Torque, Work $$=ML^{2}T^{-2}$$
Planck's constant $$=\dfrac{ML^{2}T^{-2}}{\left ( LT^{-1} \right )}\times L=ML^{2}T^{-1}$$
Hence, option B is correct.
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