Physics

# The physical quantities not having same dimensions are :

momentum and Plancks constant

##### SOLUTION
$\dfrac{1}{\sqrt{\mu _{0}\epsilon _{0}}}=\sqrt{L^{2}T^{-2}}=LT^{-1}$
Speed $=LT^{-1}$
Stress, Young's modulus
$=\dfrac{MLT^{-2}}{L^{2}}=ML^{-1}T^{-2}$
Momentum $=MLT^{-1}$
Torque, Work $=ML^{2}T^{-2}$
Planck's constant $=\dfrac{ML^{2}T^{-2}}{\left ( LT^{-1} \right )}\times L=ML^{2}T^{-1}$
Hence, option B is correct.

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Single Correct Medium Published on 18th 08, 2020
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