Physics

The ratio of dimensions electric field and magnetic field is,


ANSWER

$$LT^{-1}$$


SOLUTION
Electric field $$=$$ force/charge or $$E=F/q$$
So, $$[E]=\dfrac{[MLT^{-2}]}{[IT]}=[MLT^{-3}I^{-1}]$$ where $$[I]=$$ dimension of current.
We know that magnetic force $$F=qvB$$ or $$B=\dfrac{F}{qv}$$  
So, $$[B]=\dfrac{[MLT^{-2}]}{[IT][LT^{-1}]}=[MT^{-2}I^{-1}]$$

Thus, $$\dfrac{[E]}{[B]}=\dfrac{[MLT^{-3}I^{-1}]}{MT^{-2}I^{-1}}=[LT^{-1}]$$
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Single Correct Medium Published on 18th 08, 2020
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