Physics

The unit of an electrical parameter whose formula is $$[M^{1}L^{2}T^{-3}A^{-2}]$$ is:


ANSWER

ohm


SOLUTION
$$  V  = IR$$

So, $$ [R] = [\dfrac{V}{I}]$$$$ = [\dfrac{W}{QI} ]= [\dfrac{W}{I^{2} T}] = [\dfrac{F \times S}{I^{2} \times T}]  = [\dfrac{m \times a \times S}{I^{2} \times T}]$$$$ = [\dfrac{M(\dfrac{L}{T^{2}}) \times L}{A^{2} \times T}]$$
 
$$\Rightarrow [\Omega]= [ML^{2}T^{-3}A^{-2}]$$
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