Physics

# The unit of an electrical parameter whose formula is $[M^{1}L^{2}T^{-3}A^{-2}]$ is:

ohm

##### SOLUTION
$V = IR$

So, $[R] = [\dfrac{V}{I}]$$= [\dfrac{W}{QI} ]= [\dfrac{W}{I^{2} T}] = [\dfrac{F \times S}{I^{2} \times T}] = [\dfrac{m \times a \times S}{I^{2} \times T}]$$ = [\dfrac{M(\dfrac{L}{T^{2}}) \times L}{A^{2} \times T}]$

$\Rightarrow [\Omega]= [ML^{2}T^{-3}A^{-2}]$

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Single Correct Medium Published on 18th 08, 2020
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