Physics

Three successive measurement in an experiment gave value 10.9, 11.4042 and 11.42 the correct way of reporting the average value is:


SOLUTION
          $${ V }_{ 1 }=10.9\\ { V }_{ 2 }=11.4042\\ { V }_{ 3 }=11.42$$
Average value$$= \cfrac {10.9+11.4042+11.42}{3}$$
                        $$=11.2414$$
                        $$=11.2$$
$$\therefore$$ The  correct way of reporting the average value is $$11.2$$
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