Mathematics

Three times the complement of an angle is $$20^o$$ more than its supplement. Find the angle.


SOLUTION
Let $$x$$ be the required angle.

According to the question-

$$3 \left( 90° - x \right) = 180° - x$$

$$270° - 3x = 180° - x$$

$$\Rightarrow 3x - x = 270° - 180°$$

$$\Rightarrow x = \cfrac{90°}{2} = 45°$$
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