Mathematics

Two angles are supplementary and one angle is twice the other angle then, find the both angles.


ANSWER

$$\displaystyle { 60 }^{ o },{ 120 }^{ o }$$


SOLUTION
Let one angle be $$\displaystyle { x }^{ o }$$
then other angle is $$\displaystyle { 2x }^{ o }$$ (As twice of one angle)
Since two angles are supplementary
$$\displaystyle { x }^{ o }+{ 2x }^{ o }={ 180 }^{ o }$$
$$\displaystyle { 3x }^{ o }={ 180 }^{ o }$$
$$\displaystyle x=\frac { 180 }{ 3 } ={ 60 }^{ o }$$
One angle is $$\displaystyle { 60 }^{ o }$$,
Other angle $$\displaystyle { 2x }^{ o }=2\times { 60 }^{ o }={ 120 }^{ o }$$
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