Mathematics

Two complementary angles differ by $$10^{o}$$. Find the angles


SOLUTION

Suppose that,

One angle is $$x$$

Then other angle is $$x-{{10}^{o}}$$

We know that,

$$x+\left( x-{{10}^{o}} \right)={{90}^{o}}$$               $$\left( Complementry\,angles \right)$$

$$ 2x-{{10}^{o}}={{90}^{o}} $$

$$ 2x={{100}^{o}} $$

$$ x={{50}^{o}} $$

Then, other angle is $$x-{{10}^{o}}={{50}^{o}}-{{10}^{o}}={{40}^{o}}$$

Hence, this is the answer.
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