Mathematics

Two complementary angles differ by $10^{o}$. Find the angles

SOLUTION

Suppose that,

One angle is $x$

Then other angle is $x-{{10}^{o}}$

We know that,

$x+\left( x-{{10}^{o}} \right)={{90}^{o}}$               $\left( Complementry\,angles \right)$

$2x-{{10}^{o}}={{90}^{o}}$

$2x={{100}^{o}}$

$x={{50}^{o}}$

Then, other angle is $x-{{10}^{o}}={{50}^{o}}-{{10}^{o}}={{40}^{o}}$

You're just one step away

Subjective Medium Published on 09th 09, 2020
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