Mathematics

Two supplementary angles differ by $$44^{o}$$. Find the angles


SOLUTION

Suppose that,

One angle is $$x$$

Then other angle is $$x-{{44}^{o}}$$

We know that,

$$x+\left( x-{{44}^{o}} \right)={{180}^{o}}$$               $$\left( Suplementry\,angles \right)$$

$$ 2x-{{44}^{o}}={{180}^{o}} $$

$$ 2x={{224}^{o}} $$

$$ x={{112}^{o}} $$

Then, other angle is $$x-{{44}^{o}}={{112}^{o}}-{{44}^{o}}={{68}^{o}}$$

Hence, this is the answer.

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