Physics

Using Dimensional analysis convert newton into dyne.


SOLUTION
the dimensional formula of Force $$F = [M^1 L^1 T^{-2}]$$
So $$a =1, b=1, c=-2$$
Now because Newton is in m.k.s system, we have
$$M_1 = 1kg$$
$$L_1 = 1m$$
$$T_1 = 1s$$

$$M_2 = 1g$$
$$L_2 = 1cm$$
$$T_2 = 1s$$

$$n_1= 1 Newton$$
$$n_2 = ?$$
Using the formula
$$n_2= n_1[M1/M2]^a[L1/L2]^b[T1/T2]^c$$

$$n_2=1 [1kg/1g]^1[1m/1cm]^1[1s/1s]^{-2}$$

$$n_2=1[1000g/1g]^1[100cm/1cm]^{1\times 1}$$

$$n_2=1000×100 = 100000 = 10^5 \ dynes$$
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Subjective Medium Published on 18th 08, 2020
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