Physics

# Using Dimensional analysis convert newton into dyne.

##### SOLUTION
the dimensional formula of Force $F = [M^1 L^1 T^{-2}]$
So $a =1, b=1, c=-2$
Now because Newton is in m.k.s system, we have
$M_1 = 1kg$
$L_1 = 1m$
$T_1 = 1s$

$M_2 = 1g$
$L_2 = 1cm$
$T_2 = 1s$

$n_1= 1 Newton$
$n_2 = ?$
Using the formula
$n_2= n_1[M1/M2]^a[L1/L2]^b[T1/T2]^c$

$n_2=1 [1kg/1g]^1[1m/1cm]^1[1s/1s]^{-2}$

$n_2=1[1000g/1g]^1[100cm/1cm]^{1\times 1}$

$n_2=1000×100 = 100000 = 10^5 \ dynes$

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Subjective Medium Published on 18th 08, 2020
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