Physics

# Watt per meter kelvin is the unit of

Coefficient of thermal conductivity

##### SOLUTION
$\dfrac { Watt }{ \left( meter \right) \times \left( kelvin \right) } =\dfrac { M{ L }^{ 2 }{ T }^{ -3 } }{ LK } =M{ L }{ T }^{ -3 }{ K }^{ -1 }$
Coefficient of thermal conductivity $\left( k \right) =\dfrac { \left( \dfrac{q}{A} \right) \times \ t }{ dT }$

$\left( q/A \right) =$ heat transfer per unit area$\left( W/{ m }^{ 2 } \right)$

$dT=$ temperature difference
$t=$ thickness

$\left[ k \right] =\dfrac { \left[ M{ L }^{ 2 }{ T }^{ -3 } \right] \left[ { L }^{ -2 } \right] \left[ L \right] }{ \left[ K \right] } =M{ L }{ T }^{ -3 }{ K }^{ -1 }$

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Single Correct Medium Published on 18th 08, 2020
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