Mathematics

# Write the complement angle of:$1/5$ of $160^{o}$

##### SOLUTION
The complement angle of $(1/5\ of\ 160^{o})$ is,
$=90^{o}-(1/5\times 160^{o})$
We get
$=90^{o}-32^{o}$
$=58^{o}$
Therefore, the complement angle of $(1/5\ of\ 160^{o})$ is $58^{o}$.

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Subjective Medium Published on 09th 09, 2020
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