Mathematics

Write the complement angle of:
$$1/5$$ of $$160^{o}$$


SOLUTION
The complement angle of $$(1/5\ of\ 160^{o})$$ is,
$$=90^{o}-(1/5\times 160^{o})$$
We get
$$=90^{o}-32^{o}$$
$$=58^{o}$$
Therefore, the complement angle of $$(1/5\ of\ 160^{o})$$ is $$58^{o}$$.
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