Physics

Write the order of magnitude of mass of an electron $$9.1\times 10^{-31}$$ kg.


SOLUTION
If mass of an electron is $$9.11 X 10^{-31} kg = 9.11 X10^{-28}g$$

$$1 kg = 1000 g$$

Electrons in one kg would be = $${\dfrac{1000}{9.11 X 10^{-28}}}$$

= $${\dfrac{1000} {9.11}} X 10^{-28}$$

= $$109.76 X 10^{28}$$

= $$1.0976 X 10 ^{30}$$

=$$10^{30}$$
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