Physics

# Write the order of magnitude of mass of an electron $9.1\times 10^{-31}$ kg.

##### SOLUTION
If mass of an electron is $9.11 X 10^{-31} kg = 9.11 X10^{-28}g$

$1 kg = 1000 g$

Electrons in one kg would be = ${\dfrac{1000}{9.11 X 10^{-28}}}$

= ${\dfrac{1000} {9.11}} X 10^{-28}$

= $109.76 X 10^{28}$

= $1.0976 X 10 ^{30}$

=$10^{30}$

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Subjective Medium Published on 18th 08, 2020
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